Atomistry » Iron » Energy
Atomistry »
  Iron »
    Energy »

Iron Ionization Energy

The Iron Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Iron.
Fe -> Fe+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Iron is:
FeN+ -> Fe(N+1)+ + e-

Ionization Energy

Fe -> Fe1+ = 759.3 kJ/mol = 181.65 Kcal/mol
Fe1+ -> Fe2+ = 1561 kJ/mol = 373.44 Kcal/mol
Fe2+ -> Fe3+ = 2957 kJ/mol = 707.42 Kcal/mol
Fe3+ -> Fe4+ = 5290 kJ/mol = 1265.55 Kcal/mol
Fe4+ -> Fe5+ = 7240 kJ/mol = 1732.06 Kcal/mol
Fe5+ -> Fe6+ = 9600 kJ/mol = 2296.65 Kcal/mol
Fe6+ -> Fe7+ = 12100 kJ/mol = 2894.74 Kcal/mol
Fe7+ -> Fe8+ = 14575 kJ/mol = 3486.84 Kcal/mol
Fe8+ -> Fe9+ = 22678 kJ/mol = 5425.36 Kcal/mol
Fe9+ -> Fe10+ = 25290 kJ/mol = 6050.24 Kcal/mol

Last articles

Zn in 7VD8
Zn in 7V1R
Zn in 7V1Q
Zn in 7VPF
Zn in 7T85
Zn in 7T5F
Zn in 7NF9
Zn in 7M4M
Zn in 7M4O
Zn in 7M4N
© Copyright 2008-2020 by atomistry.com
Home   |    Site Map   |    Copyright   |    Contact us   |    Privacy